![]() SELECT unix_timestamp( time) Time format: YYYY-MM-DD HH:MM:SS or YYMMDD or YYYYMMDD Time.local( year, month, day, hour, minute, second, usec ) (or Time.gm for GMT/UTC input). Mktime( hour, minute, second, month, day, year) Get-Date -UFormat “%s” Produces: 1279152364.63599Ĭommand line: perl -e “print time” (If Perl is installed on your system)Ĭonvert from human readable date to epoch Perl Math.round(new Date().getTime()/1000.0) getTime() returns time in milliseconds. SELECT unix_timestamp(now()) More info (+ negative epochs) How to get the current epoch time in … Perl ![]() Many Unix systems store epoch dates as a signed 32-bit integer, which might cause problems on Janu(known as the Year 2038 problem or Y2038). Literally speaking the epoch is Unix time 0 (midnight ), but ‘epoch’ is often used as a synonym for ‘Unix time’. The Unix epoch (or Unix time or POSIX time or Unix timestamp) is the number of seconds that have elapsed since Janu(midnight UTC/GMT), not counting leap seconds (in ISO 8601: ). Convert from epoch to human readable date.Convert from human readable date to epoch.Put (1 + floor ( (year - 4 * floor (year / 4) + 2) / 3) ) into N3įunction floor pNumber - LiveCode has no built-in floor() functionĮnd floor T-SQL (Transact-SQL) SELECT DATEPART(DAYOFYEAR, SYSDATETIME()) or SELECT datediff(day,CAST(datepart(year,getdate()) AS CHAR(4)) + '-01-01',getdate()+1)ĪS number_of_today Go (golang) day := time.Now(). Put currentDay - firstDayofYear into totalSecondsĪnswer the round of (totalSeconds / (60*60*24)) + 1 -display total days in dialog boxĬonvert currentDate to dateItems -list of date elements separated by commas Put "January 1," & the last word of the long date into firstDayofYear -append current yearĬonvert firstDayofYear to seconds - from to first day of this yearĬonvert currentDay to seconds - from GMT to today Write-Host $DayOfYear LiveCode on mouseUp Puts time.yday Powershell $DayOfYear = (Get-Date).DayofYear Java LocalDate.now().getDayOfYear() Unix/Linux date +%j ColdFusion #dayofyear(now())# Objective C int currentDay ĭateFormatter = init] ĬurrentDay = intValue] Ĭ# int iDayOfYear = R format(Sys.Date(), "%j") Ruby time = Time.new Var onejan = new Date(this.getFullYear(),0,1) Or add a 'Day of Year' method to the date object: Select to_char(to_date('','YYYY-MM-DD'), 'DDD') from dual Delphi using DateUtils, SysUtils ĭayOfTheYear(Date) Microsoft Access DatePart("y", Now()) Visual Basic (VB.NET) Dim dayOfYear As Integer = JavaScript SELECT DAYOFYEAR('') Oracle select to_char(sysdate, 'DDD') from dual MySQL SELECT DAYOFYEAR(NOW())ĭay number between 1 and 366. Replace time with other epochs for other days. ![]() ![]() My $day_of_year = POSIX::strftime("%j", time) You can use an epoch to find other day numbers:ĭate("z") starts counting from 0 (0 through 365)!ĭay_of_year = datetime.now().timetuple().tm_yday PERL LibreOffice Calc: =ROUNDDOWN(DAYS(NOW(),DATE(YEAR(NOW()),1,1))) + 1 PHP $dayNumber = date("z") + 1 (Your date format (1-1-year) may be different) =A1-DATE(YEAR(A1),1,0) Google Docs Spreadsheet =DATEDIF(CONCAT("1-1-" year(now())) today() "D")+1Ĭalculates the difference between Jan 1 and today (=days past) then add 1 for today's daynumber. Or, for any date entered in cell A1, calculate the corresponding day-number in that date’s year: Calculate today's day-number, starting from the day before Jan 1, so that Jan 1 is day 1.
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